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5x^2+39x-44=0
a = 5; b = 39; c = -44;
Δ = b2-4ac
Δ = 392-4·5·(-44)
Δ = 2401
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2401}=49$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(39)-49}{2*5}=\frac{-88}{10} =-8+4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(39)+49}{2*5}=\frac{10}{10} =1 $
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